continue 怎么跳到上一级的循环

[yakczh]

举个例子
“A
arr=range(1,10)
skip=[3,5]

for i in arr:
for s in skip:
if i % s ==0:
continue
print(i)

本意是 被3或者5整除的数不打印, 但是这样写 貌似是跳过 skip的列表,怎么样满足条件后跳过arr

[rrfeng]

break

[rrfeng]

哦看错了……

[skydiver]

无所谓，print放里面就行了

[yuelang85]

打标记。

第一层循环一开始把flag设为0，第二层循环遇到条件就把flag设成1，紧接着break。这样就跳到了第一层循环，判断flag为1，continue。

for i in xrange(1, 10):
>>>>flag = 0
>>>>for x in xrange(1, 10):
>>>>>>>>if x == 2:
>>>>>>>>>>>>flag = 1
>>>>>>>>>>>>break
>>>>if flag == 1:
>>>>>>>>continue

[picasso250]

def can_print(i):
>>>>for s in skip:
>>>>>>>>if i % s == 0: return False
>>>>return True

for i in arr:
>>>>if can_print(i): print(i)

if you find a way hard, then u might choose the wrong way