php 获取图片链接的正则表达式 多帮我获取了一个冒号 百思不得其解求解答

[jookr]

'''php
//先定义一个获取所有图片的函数
function getSrc($content){

$pattern="/<[img|IMG].*?src=[\\\"|\\\'|\'|\"](.*?(?:[\.gif|\.jpg|\.png|\.jpeg|\.bmp]))[\\\"|\\\'|\"|\'].*?[\/]?>/i";
preg_match_all($pattern,$content,$match);
return $match;

}
//字符串
$str = ' <img src=\"http://127.0.0.1/file/upload/201503/24/1.jpg\" width=\"554\" height=\"416\" alt=\"\" />
<img src="http://127.0.0.1/file/upload/201503/24/2.jpg" width=\"550\" height=\"775\" alt=\"\" />
<img src="http://127.0.0.1/file/upload/201503/24/3.jpg" width=\"336\" height=\"508\" alt=\"\" />';

//获取并且输出
print_r(getSrc($str));

//输出内容如下
/*

Array
(
[0] => Array
(
[0] => <img src=\"http://127.0.0.1/file/upload/201503/24/1.jpg\" width=\"554\" height=\"416\" alt=\"\" />
[1] => <img src="http://127.0.0.1/file/upload/201503/24/2.jpg" width=\"550\" height=\"775\" alt=\"\" />
[2] => <img src="http://127.0.0.1/file/upload/201503/24/3.jpg" width=\"336\" height=\"508\" alt=\"\" />
)

[1] => Array
    (
        [0] => "http://127.0.0.1/file/upload/201503/24/1.jpg
        [1] => http://127.0.0.1/file/upload/201503/24/2.jpg
        [2] => http://127.0.0.1/file/upload/201503/24/3.jpg
    )

)
//为啥$str[1][0]开头的地方会带双引号呢？怎么写才能让它不带双引号
*/

[lianyue]

[\\\"|\\\'|\'|\"]
换成 () 括号 (\\\"|\\\'|\'|\")

[imn1]

@lianyue
他几乎把全部或选择的都写成[]了，能出这个结果已经算是撞大运了

[lianyue]

@imn1 我只注意到了 多余的部分

[kungfuchicken]

<img.*?src=\\?(?:\'|\")(.*?\.(?:gif|jpg|png|jpeg|bmp]))\\?(?:\'|\").*?\/?>

[kungfuchicken]

<img.*?src=\\?(?:\'|\")(.*?\.(?:gif|jpg|png|jpeg|bmp))\\?(?:\'|\").*?\/?>
更正一下