问个问题 'abcdefghigklmnopqrstuvwxyz'怎么切成 ['abc','def','ghi'…]这样的形式啊

[whnzy]

如题！

[jackal]

Javascript+正则表达式版本
<script type="text/javascript">
var str = "abcdefghigklmnopqrstuvwxyz";
var exp = /[a-z]{3}/g;
var arr = [];
var index = 0;

while ((arr = exp.exec(str)) !== null) {
console.log(arr[0]);
index = exp.lastIndex;
}
console.log(str.substring(index));
</script>

[irenicus]

perl 版
@out = ("abcdef" =~ /(...)/);

[irenicus]

那个不行
@out = split /(...)/, "abcdefghijklmnopqrstuvwxyz";
不是三的倍数也行

[xcodebuild]

@HustLiu 有道理

[extreme]

C 版：
int x = 0, y = 0;
char *string ="abcdefghigklmnopqrstuvwxyz" , three_char[9][4] = {0};
while (*string != '\0') {
three_char[x][y % 3] = *string;
y++;
if (y == 3) {
y = 0;
x++;
}
string++;
}

[saxon]

s = "abcdefghijklmnopqrstuvwxyz"
print zip(s[::3]+s[1::3]+s[2::3])
:)

[saxon]

更正，刚手滑回车
s = "abcdefghijklmnopqrstuvwxyz"
def func(s):
l = list(s)
return ''.join(l)
print map(func,zip(s[::3],s[1::3],s[2::3]))

[dofine]

def grouper(iterable, n, fillvalue=None):
"Collect data into fixed-length chunks or blocks"
# grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx
args = [iter(iterable)] * n
return izip_longest(fillvalue=fillvalue, *args)

[whnzy]

我想是不是应该再来点 C++,Golang,C#,OC,erlang,Java,Haskell.........