以下迭代如何改为函数式？

[zungmou]

Python 代码

def parse(self, data):
    tmp = data
    # funcs is a callable function iterator
    for func in funcs:
        tmp = func(tmp)
    return tmp

[yeyuexia]

reduce(lamda x, y: y(x), funcs, data)

[staticor]

递归实现 判断 funcs

[eccstartup]

funs = [(+1),(*2),(subtract 3)]
f = foldr (flip (.)) id funs
f 1

[zungmou]

@eccstartup 您这不是 Python 代码呀

[zhzy0077]

(fold-left (λ (tmp, func) (func tmp)) data funcs)