Python 遍历数组对象怎么取序号?

[QGabriel]

pymongo.cursor.Cursor list 对象
我想取 i['key'] 和 i+1['key']

怎么取?

[xiaolinjia]

enumerate

[jmc891205]

for i in range(len(list)-1)

[TimePPT]

enumerate +1

[datou]

list.index()

[QGabriel]

具体怎么写啊~以上的方法都试了好像不行啊

[1018ji]

@QGabriel for i, element in enumerate(seq):

[qW7bo2FbzbC0]

enumerate

[1018ji]

你只比较 0 和 1 我咋感觉这需求这么诡异

[xiaolinjia]

https://paste.ubuntu.com/p/t4Vy4yHJSP/

[xdnauly]

list[0].get("a") == list[1].get("a")

#还有 list[0]['a'] == list[1]['a'] 不是可以直接比较啊，没有太看懂你的问题

[QGabriel]

@xiaolinjia 谢谢!

[TenaxTsi]

@xiaolinjia 这工具不错。

[QGabriel]

@xiaolinjia list 的类型是 pymongo.cursor.Cursor db[index + 1]['a'] 就提示错误了

-----
Traceback (most recent call last):
File "C:/python/t.py", line 10, in <module>
if (item['code'] == db[index + 1]['code']):
File "C:\python\venv\lib\site-packages\pymongo\cursor.py", line 612, in __getitem__
self.__check_okay_to_chain()
File "C:\python\venv\lib\site-packages\pymongo\cursor.py", line 401, in __check_okay_to_chain
raise InvalidOperation("cannot set options after executing query")
pymongo.errors.InvalidOperation: cannot set options after executing query

[xiaolinjia]

@QGabriel 试试把他转成 list(db)，然后再操作。

[biglazycat]

list = [{'a': 1},{'a':2},{'a':3}]

for index, mem in enumerate(list):
if index < len(list) - 1:
print(mem['a'])
print(list[index + 1]['a'])

[biglazycat]

@xiaolinjia 装您的代码抄了一下。请问代码是怎么传到 ubuntu 上的？