blueimp 的 JavaScript MD5 的创建 MD5 核心功能是 binlMD5 这个 function 吗?它不是线性的吗?

2021-03-25 07:23:14 +08:00
 quxinna

function binlMD5(x, len) { /* append padding */ x[len >> 5] |= 0x80 << len % 32 x[(((len + 64) >>> 9) << 4) + 14] = len

var i
var olda
var oldb
var oldc
var oldd
var a = 1732584193
var b = -271733879
var c = -1732584194
var d = 271733878

for (i = 0; i < x.length; i += 16) {
  olda = a
  oldb = b
  oldc = c
  oldd = d

  a = md5ff(a, b, c, d, x[i], 7, -680876936)
  d = md5ff(d, a, b, c, x[i + 1], 12, -389564586)
  c = md5ff(c, d, a, b, x[i + 2], 17, 606105819)
  b = md5ff(b, c, d, a, x[i + 3], 22, -1044525330)
  a = md5ff(a, b, c, d, x[i + 4], 7, -176418897)
  d = md5ff(d, a, b, c, x[i + 5], 12, 1200080426)
  c = md5ff(c, d, a, b, x[i + 6], 17, -1473231341)
  b = md5ff(b, c, d, a, x[i + 7], 22, -45705983)
  a = md5ff(a, b, c, d, x[i + 8], 7, 1770035416)
  d = md5ff(d, a, b, c, x[i + 9], 12, -1958414417)
  c = md5ff(c, d, a, b, x[i + 10], 17, -42063)
  b = md5ff(b, c, d, a, x[i + 11], 22, -1990404162)
  a = md5ff(a, b, c, d, x[i + 12], 7, 1804603682)
  d = md5ff(d, a, b, c, x[i + 13], 12, -40341101)
  c = md5ff(c, d, a, b, x[i + 14], 17, -1502002290)
  b = md5ff(b, c, d, a, x[i + 15], 22, 1236535329)

  a = md5gg(a, b, c, d, x[i + 1], 5, -165796510)
  d = md5gg(d, a, b, c, x[i + 6], 9, -1069501632)
  c = md5gg(c, d, a, b, x[i + 11], 14, 643717713)
  b = md5gg(b, c, d, a, x[i], 20, -373897302)
  a = md5gg(a, b, c, d, x[i + 5], 5, -701558691)
  d = md5gg(d, a, b, c, x[i + 10], 9, 38016083)
  c = md5gg(c, d, a, b, x[i + 15], 14, -660478335)
  b = md5gg(b, c, d, a, x[i + 4], 20, -405537848)
  a = md5gg(a, b, c, d, x[i + 9], 5, 568446438)
  d = md5gg(d, a, b, c, x[i + 14], 9, -1019803690)
  c = md5gg(c, d, a, b, x[i + 3], 14, -187363961)
  b = md5gg(b, c, d, a, x[i + 8], 20, 1163531501)
  a = md5gg(a, b, c, d, x[i + 13], 5, -1444681467)
  d = md5gg(d, a, b, c, x[i + 2], 9, -51403784)
  c = md5gg(c, d, a, b, x[i + 7], 14, 1735328473)
  b = md5gg(b, c, d, a, x[i + 12], 20, -1926607734)

  a = md5hh(a, b, c, d, x[i + 5], 4, -378558)
  d = md5hh(d, a, b, c, x[i + 8], 11, -2022574463)
  c = md5hh(c, d, a, b, x[i + 11], 16, 1839030562)
  b = md5hh(b, c, d, a, x[i + 14], 23, -35309556)
  a = md5hh(a, b, c, d, x[i + 1], 4, -1530992060)
  d = md5hh(d, a, b, c, x[i + 4], 11, 1272893353)
  c = md5hh(c, d, a, b, x[i + 7], 16, -155497632)
  b = md5hh(b, c, d, a, x[i + 10], 23, -1094730640)
  a = md5hh(a, b, c, d, x[i + 13], 4, 681279174)
  d = md5hh(d, a, b, c, x[i], 11, -358537222)
  c = md5hh(c, d, a, b, x[i + 3], 16, -722521979)
  b = md5hh(b, c, d, a, x[i + 6], 23, 76029189)
  a = md5hh(a, b, c, d, x[i + 9], 4, -640364487)
  d = md5hh(d, a, b, c, x[i + 12], 11, -421815835)
  c = md5hh(c, d, a, b, x[i + 15], 16, 530742520)
  b = md5hh(b, c, d, a, x[i + 2], 23, -995338651)

  a = md5ii(a, b, c, d, x[i], 6, -198630844)
  d = md5ii(d, a, b, c, x[i + 7], 10, 1126891415)
  c = md5ii(c, d, a, b, x[i + 14], 15, -1416354905)
  b = md5ii(b, c, d, a, x[i + 5], 21, -57434055)
  a = md5ii(a, b, c, d, x[i + 12], 6, 1700485571)
  d = md5ii(d, a, b, c, x[i + 3], 10, -1894986606)
  c = md5ii(c, d, a, b, x[i + 10], 15, -1051523)
  b = md5ii(b, c, d, a, x[i + 1], 21, -2054922799)
  a = md5ii(a, b, c, d, x[i + 8], 6, 1873313359)
  d = md5ii(d, a, b, c, x[i + 15], 10, -30611744)
  c = md5ii(c, d, a, b, x[i + 6], 15, -1560198380)
  b = md5ii(b, c, d, a, x[i + 13], 21, 1309151649)
  a = md5ii(a, b, c, d, x[i + 4], 6, -145523070)
  d = md5ii(d, a, b, c, x[i + 11], 10, -1120210379)
  c = md5ii(c, d, a, b, x[i + 2], 15, 718787259)
  b = md5ii(b, c, d, a, x[i + 9], 21, -343485551)

  a = safeAdd(a, olda)
  b = safeAdd(b, oldb)
  c = safeAdd(c, oldc)
  d = safeAdd(d, oldd)
}
return [a, b, c, d]

}

617 次点击
所在节点    问与答
2 条回复
quxinna
2021-05-04 23:43:34 +08:00
好像是通过移位异或后面的常数项来达到非线性目的的
quxinna
2021-07-12 19:32:33 +08:00
常数值是非线性的

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