Python 每日一练：等分字符串

[ppj]

Python 每日一练 => 等分字符串

import re

# 'F0-B4-29-98-CE-34'
'-'.join(re.findall(r'.{2}', 'F0B42998CE34'))

使用场景：字符串平均切割、MAC 地址切割等操作。

[krixaar]

from textwrap import wrap

# 'F0-B4-29-98-CE-34'
'-'.join(wrap('F0B42998CE34', 2))

[ppj]

@krixaar 嗯嗯，多谢哈。

[wang9571]

'-'.join(s[x:x+2] for x in range(0, len(s), 2))

[Geekgogo]

@krixaar #1 学到老活到老

[piglei]

好答案前面有了，我再多贡献一条基于正则的花活。若干年前学自《精通正则表达式》，对于当时的我过于震撼，牢记至今：

>>> s = 'F0B42998CE34'
>>> import re
>>> re.sub(r'(?<=.)(?=(..)+$)', '-', s)
'F0-B4-29-98-CE-34'

[l4ever]

string='20220202'
# out put-> 2022-02-02
楼下的请解答

[elboble]

''.join([(str[i]+('-' if i%2 and not (i==1 or i == len(str)-1) else '')) for i in range(len(str))])

[brucmao]

```python

s = 'F0B42998CE34'

def chunk(iterable, chunk_size, on_chunk=None):
on_chunk = on_chunk or (lambda x:x)
return [on_chunk(chunk) for chunk in zip(*[iter(iterable)] * chunk_size)]

res = chunk(s,2,''.join)
print('-'.join(res))



```
https://github.com/lisonge/lisonge.gitHub.io/raw/main/1x1.png#YGBgcHl0aG9uCgpzID0gJ0YwQjQyOTk4Q0UzNCcKCmRlZiBjaHVuayhpdGVyYWJsZSwgY2h1bmtfc2l6ZSwgb25fY2h1bms9Tm9uZSk6CiAgICBvbl9jaHVuayA9IG9uX2NodW5rIG9yIChsYW1iZGEgeDp4KQogICAgcmV0dXJuIFtvbl9jaHVuayhjaHVuaykgZm9yIGNodW5rIGluIHppcCgqW2l0ZXIoaXRlcmFibGUpXSAqIGNodW5rX3NpemUpXQoKcmVzID0gY2h1bmsocywyLCcnLmpvaW4pCnByaW50KCctJy5qb2luKHJlcykpCgoKCmBgYA==