python 如何优雅地抛出异常

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如果我执行错误的代码， python 原生的抛出异常能处理得非常优雅：

>>> print a
File "<stdin>", line 1
 print a
       ^
SyntaxError: Missing parentheses in call to 'print'

自己写的代码如何才能这么优雅地抛出异常呢？

Supplement 1 · Sep 30, 2015

恩，我指的就是下面的这个 "^"

Python

优雅

代码

6 replies • 2015-10-03 12:05:37 +08:00

clino

Sep 30, 2015

我感觉你是想说打印出 traceback 吧?

chengzhoukun

Sep 30, 2015

http://blog.csdn.net/handsomekang/article/details/9373035

import traceback
try:
print a
except Exception as e:
traceback.print_exc()

chengzhoukun

Sep 30, 2015

这个更详细： http://my.oschina.net/chihz/blog/180573

fengjianxinghun

Sep 30, 2015

抛异常和捕获是 2 个事吧。。。

DiffView

Oct 1, 2015

写个 log 模块比如 https://www.fancycoding.com/custom-python-log-module/
然后
try:
momoda
except Exception as e:
LogC(self, traceback.format_exc())

得到
2014-12-06 15:10:56,818 - C - CRITICAL - you can't momoda me

deangl

Oct 3, 2015 via Android

logging.exception(e)
这个？