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Python 的 sax 解析 xml 文件遇到了个错误,不知各位大佬有解决办法否?

  •  1
     
  •   onyourroad · 2018-04-21 19:26:21 +08:00 · 799 次点击
    这是一个创建于 594 天前的主题,其中的信息可能已经有所发展或是发生改变。

    a.xml:

    <?xml version="1.0" encoding="ISO-8859-1"?>
    <!DOCTYPE dblp SYSTEM "dblp.dtd">
    <article mdate="2017-05-28" key="journals/acta/Saxena96">
        <author>Sanjeev Saxena</author>
        <author>q</author>
        <author>w</author>
        <title>Parallel Integer Sorting and Simulation Amongst CRCW Models</title>
        <pages>607-619</pages>
        <year>1996</year>
        <volume>33</volume>
        <journal>Acta Inf</journal>
        <number>7</number>
        <url>db/journals/acta/acta33.html#Saxena96</url>
        <ee>htt</ee>
    </article>
    
    

    python 代码:

    from xml.sax.handler import ContentHandler, EntityResolver
    from xml.sax import parse
    from itertools import combinations
    
    
    class DBLP(ContentHandler, EntityResolver):
        passthrough = False
        paper_authors = []
        currTag = ''
    
        def startElement(self, name, attrs):
            if name == 'article':
                self.passthrough = True
            elif name == 'author' and self.passthrough:
                self.currTag = 'author'
    
        def endElement(self, name):
            if name == 'article':
                self.passthrough = False
                self.generate_paper_info()
                self.paper_authors = []
            elif name == 'author':
                self.currTag = ''
    
        def characters(self, chars):
            if self.passthrough and self.currTag == 'author':
                self.paper_authors.append(chars)
    
        def generate_paper_info(self):
            with open('dblp.txt', 'w') as f:
                if len(self.paper_authors) < 2:
                    print 'Only one author'
                else:
                    for info in combinations(self.paper_authors, 2):
                        f.write('{0} {1}\n'.format(info[0], info[1]))
                        print 'Write one piece of cooperation user'
                        
                        
     parse('a.xml', DBLP())
    

    报错信息:

    Traceback (most recent call last):
      File "dblp.py", line 40, in <module>
        parse('a.xml', DBLP())
      File "E:\Python2.7.12\lib\xml\sax\__init__.py", line 33, in parse
        parser.parse(source)
      File "E:\Python2.7.12\lib\xml\sax\expatreader.py", line 110, in parse
        xmlreader.IncrementalParser.parse(self, source)
      File "E:\Python2.7.12\lib\xml\sax\xmlreader.py", line 123, in parse
        self.feed(buffer)
      File "E:\Python2.7.12\lib\xml\sax\expatreader.py", line 213, in feed
        self._parser.Parse(data, isFinal)
      File "E:\Python2.7.12\lib\xml\sax\expatreader.py", line 397, in external_entity_ref
        "")
      File "E:\Python2.7.12\lib\xml\sax\saxutils.py", line 349, in prepare_input_source
        f = urllib.urlopen(source.getSystemId())
      File "E:\Python2.7.12\lib\urllib.py", line 87, in urlopen
        return opener.open(url)
      File "E:\Python2.7.12\lib\urllib.py", line 213, in open
        return getattr(self, name)(url)
      File "E:\Python2.7.12\lib\urllib.py", line 469, in open_file
        return self.open_local_file(url)
      File "E:\Python2.7.12\lib\urllib.py", line 483, in open_local_file
        raise IOError(e.errno, e.strerror, e.filename)
    IOError: [Errno 2] : 'dblp.dtd'
    

    分割线~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~·

    <!DOCTYPE dblp SYSTEM "dblp.dtd">
    

    只要把上面这句去掉就好了,想到用 EntityResolver 重写,忽略识别 dtd,但是不知道如何重写。

    目前尚无回复
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