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zcsnbb
V2EX  ›  Python

Python TypeError: argument of type 'type' is not iterable 这个问题怎么解决

  •  
  •   zcsnbb · Oct 22, 2018 · 16553 views
    This topic created in 2944 days ago, the information mentioned may be changed or developed.

    self.is_back_test = params['is_back_test'] if "is_back_test" in params else False TypeError: argument of type 'type' is not iterable

    这哥问题应该怎么解决

    已经尝试过 self.is_back_test = params['is_back_test'] if "is_back_test" in params.keys() else False

    使用的是 python3

    8 replies  •  2018-10-22 17:08:50 +08:00
    conn4575
    conn4575
    Oct 22, 2018 via Android
    1
    检查一下 params 是否是 None?
    monkeylyf
    monkeylyf
    Oct 22, 2018
    2
    和楼上意见一致。params 应该不是 dict。你可以 print(type(params)) 试试
    Yourshell
    Yourshell
    Oct 22, 2018 via iPhone
    3
    你参数的类型不对啊,你先判断是不是可迭代对象啊,报错都这么明显了。
    bany
    bany
    Oct 22, 2018❤️1
    4
    ```python
    if isinstance(params, dcit):
    return params.get('is_back_test', False)
    else:
    return False
    ```
    laike9m
    laike9m
    Oct 22, 2018 via Android
    5
    请贴上可以复现问题的代码谢谢
    zcsnbb
    zcsnbb
    OP
    Oct 22, 2018
    6
    @conn4575 找到问题了 我忘了传参数 感谢
    zcsnbb
    zcsnbb
    OP
    Oct 22, 2018
    7
    @monkeylyf 问题解决了 感谢
    zcsnbb
    zcsnbb
    OP
    Oct 22, 2018
    8
    @bany 感谢!!!
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