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cs5117155
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二进制数据累加求和,取低八位

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  •   cs5117155 · 159 天前 · 767 次点击
    这是一个创建于 159 天前的主题,其中的信息可能已经有所发展或是发生改变。

    以下是 16 进制表示,我把每一个 16 进制转换成 10 进制,然后进行累加,得到 2551

    echo 2551&0xff;
    

    转换成 16 进制是f7

    5a 54 08 1f 01 01 61 00 50 53 0a 09 4e 01 64 00 00 00 00 00 00 00 00 00 00 00 00 02 00 00 00 00 00 00 00 00 50 53 0a 09 4f 03 64 00 00 00 00 00 00 00 50 53 0a 09 46 04 64 00 00 00 00 00 00 00 50 53 0a 0a 09 05 64 00 00 00 00 00 00 00 50 53 0a 0a 08 06 64 00 00 00 00 00 00 00 50 53 0a 09 34 07 64 00 00 00 00 00 00 00 50 53 0a 0a 0a 08 64 00 00 00 00 00 00 00
    

    但是硬件那边传过来的求和校验是0x47,是我哪里算错了吗

    4 条回复    2021-05-11 11:58:05 +08:00
    aa65535
        1
    aa65535   159 天前
    明明加起来是 2631,不知道你为什么能得到 2551
    SingeeKing
        2
    SingeeKing   159 天前
    >>> sum([int(x, 16) for x in '''5a 54 08 1f 01 01 61 00 50 53 0a 09 4e 01 64 00 00 00 00 00 00 00 00 00 00 00 00 02 00 00 00 00 00 00 00 00 50 53 0a 09 4f 03 64 00 00 00 00 00 00 00 50 53 0a 09 46 04 64 00 00 00 00 00 00 00 50 53 0a 0a 09 05 64 00 00 00 00 00 00 00 50 53 0a 0a 08 06 64 00 00 00 00 00 00 00 50 53 0a 09 34 07 64 00 00 00 00 00 00 00 50 53 0a 0a 0a 08 64 00 00 00 00 00 00 00'''.strip().split()])
    2631
    takitooru
        3
    takitooru   159 天前
    uint8_t test_list[]={0x5a,0x54,0x08,0x1f,0x01,0x01,0x61,0x00,0x50,0x53,0x0a,0x09,0x4e,0x01,0x64,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x53,0x0a,0x09,0x4f,0x03,0x64,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x53,0x0a,0x09,0x46,0x04,0x64,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x53,0x0a,0x0a,0x09,0x05,0x64,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x53,0x0a,0x0a,0x08,0x06,0x64,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x53,0x0a,0x09,0x34,0x07,0x64,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x53,0x0a,0x0a,0x0a,0x08,0x64,0x00,0x00,0x00,0x00,0x00,0x00,0x00};
    int main(int argc,char *argv[])
    {
    uint8_t rst = 0;
    for(int i=0;i<sizeof(test_list);i++)
    {
    rst += test_list[i];
    }
    printf("%d 0x%02x",rst,rst);
    }
    gcc .\test6_sig.c -m32
    .\a.exe
    -> 71 0x47
    cs5117155
        4
    cs5117155   158 天前
    谢谢大家,原来我自已程序过滤了一个字节,导致结果错误了,2631 是对的
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